What is the percentage change in the tension necessary in a sonometer of fixed length to produce a note one octave lower (half of original frequency) than before?
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a
25%
b
50%
c
67%
d
75%
answer is D.
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Detailed Solution
In Sonometer V ∝ T∴ V1V2 = 2 = T1T2 ⇒T2 = T14T1-T2T1×100 = T1-T14T1×100 = 75%