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What is the phase difference between two simple harmonic motions represented by
$x_{1} = A \sin (ωt + \frac{π}{6})$ and $x_{2} = A cosωt ?$

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Correct option is B

Given, x1=A sin ωt+π6 and x2=A cosωt⇒ x2=Asinωt+π2Phase difference, Δϕ=ϕ2-ϕ1⇒Δϕ=π2-π6⇒ Δϕ=3π-π6=π3

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What is the phase difference between two simple harmonic motions represented byx1=A sin ωt+π6 and x2=A cosωt ?

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

What is the phase difference between two simple harmonic motions represented by
$x_{1} = A \sin (ωt + \frac{π}{6})$ and $x_{2} = A cosωt ?$