What is the power output of 92U235 reactor if it takes 30 days to use up 2 kg of fuel and if each fission gives 185 MeV of usable energy? Avogadro's number = 6.02 × 1026 per kilomole.

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45 megawatt

58.46 megawatt

72 megawatt

92 megawatt

answer is B.

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Detailed Solution

Number of atoms in 2kg fuel = 2235=6.02×1026=5.12×1024Fissions rate =Number of atoms fissioned in one second = 5.12×102430×24×60×60=1.975×1018s-1Each fission gives 185MeV. Hence, energy obatined in one second,P=185×1.975×1018MeVs-1

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