Question

What is the range of a projectile thrown with velocity 98 ms^-1 with angle 30° from horizontal?

Moderate

Solution

Given, u = 98 ms^-1 and $θ$ = 30°
$∵$ Range of a projectile,
$R = \frac{u^{2} \sin (2 θ)}{9} = \frac{98 \times 98 \times \sin 60 °}{9.8}$
$R = 490 \sqrt{3} m$

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