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Q.

At what rate should light energy be allowed to fall normally on a perfectly reflecting mirror with 1  cm2 of area for one hour such that the force that acts on the mirror is 6.7× 10−8  N ?

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a

1 Wcm2

b

8 Wcm2

c

10 Wcm2

d

None of these

answer is C.

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Detailed Solution

If I be the intensity of light, ThenF=2IAC   ⇒   I=FC2.A=  6.7 × 10−8 × 3 × 1082  ×  1  W/cm2⇒   I=10   W/cm2
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