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Q.

What is the ratio of the circumference of the first Bohr orbit for the electron in the hydrogen atom to the de Broglie wavelength of electrons having the same velocity as the electron in the first Bohr orbit of the hydrogen atom?

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a

1:1

b

1:2

c

1:4

d

2:1

answer is A.

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Detailed Solution

mvr=nh2π,λ=hmv  Using the two concept we get, mvr=nh2π( where n=1 )  2πr=1×hmv...............(1) λ=hmv...............(2)  Divide (2) by (1),2πrλ=h×mvmv×h=11=1:1
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