What is ratio of surface energy of 1 small drop and 1 large drop, if 1000 small drops combined to form 1 large drop
100 : 1
1000 : 1
10 : 1
1 : 100
Volume of liquid remain same i.e. volume of 1000 small drops will be equal to volume of one big drop
n43πr3=43πR3⇒1000r3=R3⇒R=10r∴rR=110 surface energy of one small drop surface energy of one big drop =4πr2T4πR2T=1100