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Q.

What is the resultant magnetic field induction at the third corner, if two unlike poles, each of strength ‘m’ are placed at the two corners of an equilateral triangle of side ‘a’

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a

Bnet=μ04πma2

b

Bnet=2μ04πma2

c

Bnet=3μ04πma2

d

Bnet=6μ04πma2

answer is A.

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Detailed Solution

Magnetic field induction at the point ‘C’ due to the North pole is away from its                                                           B1=μ04πma2Magnetic field induction at the point C due to the south pole is towards the pole                                                            B2=μ04πma2Applying parallelogram Law of Vectors                                                          B1=B2=μ04πmd2=B [Let say] from figure , θ=120°∴Bnet =B2+B2+2B2cos120°⇒Bnet =B2+B2-B2 ⇒Bnet =B=μ04πmd2, this is the magnitude of the resultant induction at the third corner with the direction being parallel to line connecting the north pole to the south pole
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