What is the resultant magnetic field induction at the third corner, if two unlike poles, each of strength ‘m’ are placed at the two corners of an equilateral triangle of side ‘a’
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Bnet=μ04πma2
b
Bnet=2μ04πma2
c
Bnet=3μ04πma2
d
Bnet=6μ04πma2
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Magnetic field induction at the point ‘C’ due to the North pole is away from its B1=μ04πma2Magnetic field induction at the point C due to the south pole is towards the pole B2=μ04πma2Applying parallelogram Law of Vectors B1=B2=μ04πmd2=B [Let say] from figure , θ=120°∴Bnet =B2+B2+2B2cos120°⇒Bnet =B2+B2-B2 ⇒Bnet =B=μ04πmd2, this is the magnitude of the resultant induction at the third corner with the direction being parallel to line connecting the north pole to the south pole