What should be the angular velocity of rotation of the earth about its own axis so that the weight of a body at the equator reduces to 2/5 of its present value? (Take R as the radius of the earth)
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a
g3R
b
2g3R
c
3g5R
d
2g7R
answer is C.
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Detailed Solution
mg′=mg−mRω2cos2ϕ Now, 25mg=mg−mRω2 or mRω2=mg−25mg=35mg or ω=3g5R