Questions
What should be the velocity of earth due to rotation about its own axis so that the weight at equator become 3/5 of initial value. Radius of earth on equator is 6400 km
a
7.4×10−4 rad/sec
b
6.7×10−4 rad/sec
c
7.8×10−4 rad/sec
d
8.7×10−4 rad/sec
detailed solution
Correct option is C
Weight of the body at equator = 35 of initial weight ∴g′=35g (because mass remains constant)g′=g−ω2Rcos2λ⇒35g=g−ω2Rcos20∘⇒ω2=2g5R⇒ω=2g5R=2×105×6400×103=7.8×10−4radsecTalk to our academic expert!
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The angular speed of earth, so that the object on equator may appear weightless, is , radius of earth 6400 km)
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