First slide

Photo Electric Effect

Question

What is the stopping potential when the metal with work function 0.6 eV is illuminated with the light of 2 eV?

Easy

A

2.6 V
B

3.6 V
C

0.8 V
D

1.4 V

Solution

$V_{o} = \frac{(E - W_{o})}{e} = \frac{(2 eV - 0 .6 eV)}{e} = 1 .4 V$

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