At what temperature will the rms speed of oxygen molecule will be sufficient for escaping from the earth?
ve=11.2 km s−1, mass of oxygen molecule=2.76×10−26 kg and k=1.38×10−23J k−1
1000 K
(B) 2000 K
45000 K
83600 K
Let the temperature be T.According to kinetic theory of gases, translational KE=32kTThe oxygen molecule will escape from earth if, 32kT>12mve2i.e., T>mve23k or T>2.76×10−26×(11.2×103)23×1.38×10−23T>8.36×104K.