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At what temperature will the rms speed of oxygen molecules become just sufficient for escaping from the Earth's atmosphere?
Given: Mass of oxygen molecule (m) : $2.76 x 10^{- 26} kg$ ;
Boltzmann's constant $k_{B}$ = 1.38x $10^{- 23}$ ${JK}^{- 1}$ )

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1.254×104 K

2.508 × 104 K

5.016×104 K

8.360×104K

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detailed solution

Correct option is D

Ves= Vrms11.2 × 103 = 3kBTm⇒T = (11.2×103)2m3kBPutting value of m and kBT = 8.360×104 K

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At what temperature will the rms speed of oxygen molecules become just sufficient for escaping from the Earth's atmosphere? Given: Mass of oxygen molecule (m) : 2.76x 10-26 kg ; Boltzmann's constant kB = 1.38x 10-23 JK-1 )

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

At what temperature will the rms speed of oxygen molecules become just sufficient for escaping from the Earth's atmosphere?
Given: Mass of oxygen molecule (m) : $2.76 x 10^{- 26} kg$ ;
Boltzmann's constant $k_{B}$ = 1.38x $10^{- 23}$ ${JK}^{- 1}$ )