At what temperature will the rms speed of Oxygen molecules become just sufficient for escaping from the Earth’s atmosphere? (Given : Mass of oxygen molecule (m) = 2.76×10–26 kg and Boltzmann’s constant k =1.38×10–23 JK–1)

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2.508×104 K

8.360×104 K

1.254×104 K

5.016×104 K

answer is B.

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Detailed Solution

Vesc = VrmsT=11.2×1032m3k=

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