At what time PE will be equal to half of the total energy (TE) in SHM of time period T

Potential energy of particle in SHM is given as12mω2A2cos2ωtTotal energy of particle in SHM is given as 12mω2A2According to question,12mω2A2sin2ωt=1212mω2A2sin2ωt=12=sin2π4⇒ωt=π4⇒t=π4ω=π×T4×2π⇒t=T8