Q.
what is the torque of the force F=2i-3j+4k. F acting at the point r=3i+ 2j+3k m about origin.
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a
6i-6j+12k
b
17i-6j-13k
c
-6i+6j-12k
d
-17i+6j+13k
answer is B.
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Detailed Solution
τ→=r×F=ijk3232-34=i[2x 4- 3(-3)] +j[3x2-4x3] +k[3(-3)-2x2]=i17+j(-6) +k(-13)=17i-6j-13k