What is the unit vector perpendicular to the following vectors 2i^+2j^−k^ and 6i^−3j^+2k^?
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a
i^+10j^−18k^517
b
i^−10j^+18k^517
c
i^−10j^−18k^517
d
i^+10j^+18k^517
answer is C.
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Detailed Solution
A→=2i^+2j^−k^ and B→=6i^−3j^+2k^C→=A→×B→=(2i^+2j^−k^)×(6i^−3j^+2k^)=i^j^k^22−16−32=i^−10j^−18k^ Unit vector perpendicular to both A→ and B→=i^−10j^−18k^12+102+182=i^−10j^−18k^517