What is the value of inductance L for which the current is maximum in a series LCR circuit with C=10 μF and ω=1000 s−1?

In resonance condition, maximum current flows in the circuit.Current in LCR series circuit,i=VR2+XL−XC2Where V is rms value of current, R is resistance, XL is inductive reactance and XC is capacitive reactance. For current to be maximum,XL=XCThis happens in resonance state of the circuit, i.e.,ωL=1ωCor     L=1ω2C                            ….(i)Given, ω=1000 s−1, C=10 μF=10 × 10−6 FHence, L=1(1000)2×10×10−6=0.1H=100 mH