what is the value of linear velocity of a particle if its angular velocity is ω→=3i−4j+k and ins tantaneous positon vector is r→=5i−6j+6k ?
6i+2j-3k
-18i-13j+2k
4i-13j+6k
6i-2i+8k
We know that v→=ω→×r→∴v→=ijk3−415−66=i(−24+6)+j(5−18)+k(−18+20)=−18i−13j+2k