First slide

Applications of SHM

Question

What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of 10cm (g = 9.8 m/s2)

Moderate

A

2.2 m/s
B

1.8 m/s
C

1.4 m/s
D

0.6 m/s

Solution

According to the principle of conservation of energy, $\frac{1}{2} {mv}^{2} = mgh$ or $v = \sqrt{2 gh} = \sqrt{2 \times 9 .8 \times 0 .1} = 1 .4 m / s .$

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