What will be the minimum number of capacitors having rating 8μF and 250 V that will be required to make a composite capacitor having rating 16 μF and 1000 V?

Minimum number of capacitors in each row =1000250=4Therefore, 4 capacitors connected n series.If there are m such rows, then total capacity=m×2=6       ∴  m= 16/2 = 8∴   minimum number of capacitors=4×8=32