What will be the nature of water from a circular tap, when its flow rate increased from 0.18 L/min to 0.48 L/min ? The radius of the tap and viscosity of water are 0.5 cm and 10-3 Pa-s, respectively. (Density of water :103 kg/m3)

Speed ,  V=QAV1=0.18×10−3π(0.5×10−2)2×60=0.03819 m/s      V2=0.48×10−3π(0.5×10−2)2×60=0.1019 m/s  Reynolds number  Re=ρVDη For Q1 ,    Re=103×0.03819×10-210-3=381.9<1000  ​​​​(steady flow)  For Q2 ,    Re=103×0.1019×10-210-3=1019>1000  ​​​​(unsteady flow)