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Q.

What will be the speed of an electron if it's de Broglie wavelength is equal to 10−3 times the wavelength of a photon of frequency 6×1014Hz?  (Speed of light 3×108m/s; Planck's constant =6.63×10−34J.s; Mass of electron =9.1×10−31kg

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a

1.7×106m/s

b

1.45×106m/s

c

1.8×106m/s

d

1.1×106m/s

answer is B.

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Detailed Solution

For photon v=cλλp=Cv=3×1086×1014=12×10−6mFor electronλe=10−3×λp=10−92mλ=hp,p=mvV=hλm=6.63×10−3412×10−9×9.1×10−31=1.45×106
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