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Calorimetry

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By Expert Faculty of Sri Chaitanya
Question

What will be the temperature, when 150 g of ice at 0°C is mixed with 300 g of water at 50°C? Specific heat of water =1 ca lg-1°C. Latent heat of fusion of ice = 80 -1 ca lg-1.

Moderate
Solution

Let us assume that T > 0° C

Heat lost by water = Heat gained by ice to melt + heat gained by water formed from ice

300×1×(50T)=150×80+150×1×(T0) T=6.7C

Hence, our assumption that T > 0°C is correct.


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