What will be the temperature, when 150 g of ice at 0°C is mixed with 300 g of water at 50°C? Specific heat of water =1 ca lg-1°C. Latent heat of fusion of ice = 80 -1 ca lg-1.

Let us assume that T > 0° CHeat lost by water = Heat gained by ice to melt + heat gained by water formed from ice300×1×(50−T)=150×80+150×1×(T−0)⇒ T=6.7∘CHence, our assumption that T > 0°C is correct.