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Q.

In Wheat stone’s bridge shown in the adjoining figure galvanometer gives no deflection on pressing the key, the balance condition for the bridge is :

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a

R1R2=C1C2

b

R1R2=C2C1

c

R1R1+R2=C1C1−C2

d

R1R1−R2=C1C1+C2

answer is C.

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Detailed Solution

At balance, the potentials of point B and D are same and there will be no current in the arm BD. Thus,i1R1=qC1...(1)where q is the charge on both the capacitor plates connected in series.Quite similarly VB−VC=VD−VCor i1R2=qC2...(2)Dividing eqs. (i) and (ii), we getR1R2=C2C1
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