First slide

Thermal expansion

Question

A wheel is $80.3 c m$ in circumference. Its iron tyre measures 80cm around its inner face. If the coefficient of linear expansion for iron is $12 \times 10^{- 6} /^{0} C$ , the temperature of the tyre must be raised by

Moderate

A

$105^{0} C$
B

$223^{0} C$
C

$312 . 5^{0} C$
D

$417^{0} C$

Solution

$c o e f f i c i e n t o f l i n e a r e x p a n s i o n o f s o l i d i s 80 c m; Δ t i s c h a n g e i n t e m p e r a t u r e α = \frac{Δ l}{l Δ t} \Rightarrow Δ t = \frac{Δ l}{l α} s u b s t i t u t e g i v e n v a l u e s i n a b o v e e q u a t i o n Δ t = \frac{0.3}{80 \times 12 \times 10^{- 6}} Δ t = \frac{1}{8 \times 4 \times 10^{- 4}} Δ t = \frac{100 \times 100}{8 \times 4} = \frac{625}{2} = {312.5}^{0} C = t e m p e r a t u r e o f t y r e m u s t b e r a i s e d$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App