A wheel is 80.3cm  in circumference. Its iron tyre measures 80cm around its inner face. If the coefficient of linear expansion for iron is 12×10−6/0C , the temperature of the tyre must be raised by

coefficient of linear expansion of solid is 80 cm ; Δt is change in temperature α=ΔllΔt ⇒Δt=Δllα substitute given values in above equation Δt=0.380×12×10−6 Δt=18×4×10−4 Δt=100×1008×4=6252=312.50C=temperature of tyre must be raised