A wheel comprises a ring of radius R and mass M and three spokes each of mass m. The moment of inertia of the wheel about its axis is

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M+m4R2

(M+m)R2

(M+3m)R2

M+m2R2

answer is B.

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Detailed Solution

The moment of inertia, I=Iring +3Ispoke =MR2+3mR23=(M+m)R2

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