A wheel having moment of inertia 2 kg-m2 about its vertical axis, rotates at the rate of 60 rpm about an axis. The torque which can stop the wheel's rotation in the minute would be :

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π12N−m

π15N−m

π18N−m

2π15N−m

answer is B.

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Detailed Solution

From τ=Iα and ω=ω0+αt where ω0=60×2π60=2πrad/sWe have τ=Iω0t=22π60=π15N−m

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