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Q.

A wheel, starting from rest, rotates with a uniform angular acceleration of 2 rad/sec .Then the number of rotations it performs in tenth second is

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a

3

b

6

c

9

d

12

answer is A.

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Detailed Solution

ω0=0Sn=u+12a(2n−1)⇒θ10=α2(2n−1)=22(2×10−1)=19 rad. Number of revolutions 192π=3

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