When an ac source of emf e = E0 sin(100 t) is connected across a circuit, the phase difference between emf e and current i in the circuit is observed to be p/4 as shown in Fig. If the circuit consists possibly only of R-C or L-C or L-R series, find the relationship between the two elements.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
R = 1kW, C = 10 mF
b
R = 1 kW, C = 1 mF
c
R = 1 kW, L = 10 H
d
R =1 kW, L = 1 H
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Fig. shows that current i leads the emf e by a phase angle π/4. Therefore, the circuit can be R-C circuit alone.tanϕ=XCR=1ωCR=tanπ4=1. e=E0sin100t,ω=100rad/s∴CR=1ω=1100, R=1KΩ=103ΩSolving C=1ωR=10μF