First slide

Capacitance

Question

When an additional charge of 2C is given to a capacitor, energy stored in it is increased by 21 %. The original charge of the capacitor, is :

Easy

A

30 C
B

40 C
C

10 C
D

20 C

Solution

$U = \frac{Q^{2}}{2 C} \Rightarrow \frac{{(Q_{0} + 2)}^{2}}{2 C} = 1.21 \frac{{Q_{0}}^{2}}{2 C} \Rightarrow Q_{0} = 20 C$

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