First slide

Electrostatic force

Question

When air is replaced by a dielectric medium of constant k, the maximum force of attraction between two charges separated by a distance

Easy

A

Decreases k times
B

Remains unchanged
C

Increases k times
D

Increases k^-1 times

Solution

$F^{'} = \frac{1}{4 {πε}_{0}} \frac{q_{1} q_{2}}{r^{2}} = \frac{F}{K}$
If F is the force in air, then $F^{'}$ is less than F since $K > 1$ .

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