When the angular velocity of a uniformly rotating body has increased thrice, the resultant of force applied to it increases by 60 newton. Find the acceleration of the body in two cases. The mass of the body, m = 3 kg
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a
2⋅5m/s2,7⋅5m/s2
b
7⋅5m/s2,22⋅5m/s2
c
5m/s2,45m/s2
d
2⋅5m/s2,22⋅5m/s2
answer is D.
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Detailed Solution
Given, F1=mrω02and F2=mr3ω02∴ ΔF=F2−F1=mr9ω02−ω02=8mrω02or 60×8×3×rω02 or rω02=(60/24)Now a1=rω02=60/24=2⋅5m/s2and a2=arω02=9×2⋅5=22⋅5m/s2