When a ball is thrown up vertically with velocity v0 . It reaches a maximum height of h . If one wishes to triple the maximum height then the ball should be thrown with velocity
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a
3v0
b
3v0
c
qv0
d
3v0/2
answer is A.
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Detailed Solution
Here x'=(v'v)2x or 3h=(v'v0)2h ∴v'=v03 As v2=u2+2as So 0+v02+2(−g)h (or) v0=2gh Or v0αh When h'=3h then v0'=h'=3h ∴v0'v0=3hh=3 (or) v0'=3v0