When a bar magnet is placed at 900 to a uniform magnetic field. It is acted upon by a couples which is maximum. For the couple to be half of the maximum value at what angle should the magnet be inclined to the magnetic field B

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300

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900

answer is A.

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Detailed Solution

We know τ=MBsinθ If θ=900 then , τmax=MB Let say at angle that θ , max torque becomes half, ⇒12τmax=MBsinθ ⇒MB2=MBsinθ⇒sinθ=12⇒sinθ=sin30°⇒θ=30°

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