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Q.

When a bar magnet is placed at 900 to a uniform magnetic field. It is acted upon by a couples  which is maximum. For the couple to be half of the maximum value at what angle should the magnet be inclined to the magnetic field B

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a

300

b

450

c

600

d

900

answer is A.

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Detailed Solution

We know  τ=MBsinθ            If   θ=900           then , τmax=MB Let say at angle that θ , max torque becomes half, ⇒12τmax=MBsinθ ⇒MB2=MBsinθ⇒sinθ=12⇒sinθ=sin30°⇒θ=30°
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