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When a belt moves horizontally at a constant speed of 1.5 m/s, gravel is falling on it at  5kg/s, then the extra power needed to drive the belt is :

a
11.25 W
b
37.5 W
c
7.5 W
d
0.75 W

detailed solution

Correct option is A

GivenConstant speed v=1.5 m/sdmdt=5 kg/sFrom Newton’s law F=dpdt∵p=mv⇒F=dmvdt=v.dmdtF=vdmdt=1.5×5=7.5 NPower P=F×v=7.5×1.5=11.25 W

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