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When a big drop of water is formed from n small drops of water, the energy loss is 3 E, where E is the energy of the bigger drop. If R is the radius of the bigger drop and r is the radius of the smaller drop, then number of smaller drops (n) is :

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a

4Rr

b

2R2r

c

4R2r2

d

4Rr2

answer is C.

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Detailed Solution

n×4πr2T−4πR2T=3ER=n1/3rn×4πr2T=4×4πR2Tn=4R2r2

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When a big drop of water is formed from n small drops of water, the energy loss is 3 E, where E is the energy of the bigger drop. If R is the radius of the bigger drop and r is the radius of the smaller drop, then number of smaller drops (n) is :