First slide
Fluid statics
Question

 When a block of iron floats in mercury at 0oC, a fraction k1, of its volume is submerged, while at the temperature 600 C, a fraction k2, is submerged. If the
coefficient of volume expansion of iron is γFe and that of mercury isγFe , then the ratio ,k1 / k2 can be expressed as

Moderate
Solution

 let M be the mass of iron block and V its volume. Then
Mg=Fe(0)g=k1Hg or ρFe(0)=k1ρHg(0) and Mg=Fe(60)g=k2Hg(60)g or ρFe(60)=k2ρHg(60)  ρFe(0)ρFe(60)=k1k2×ρHg(0)ρHg(60)  Now  ρFe(60)=ρFe(0)1+60γFe  and ρHg(60)=ρHg(0)1+60γHg  k1k2=ρFe(0)ρFe(60)×ρHg(60)ρHg(0)=1+60γFe1+60γHg

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