When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l).The elastic potential energy stored in the extended wire is [NEET 2019]
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a
MgL
b
12Mgl
c
12MgL
d
Mgl
answer is B.
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Detailed Solution
In stretching a wire, the work done against internal restoring force is stored as elastic potential energy inthe wire and is given byU=W=12× Force (F)×Elongation (/)=12Fl=12×Mg×l=12Mgl