First slide

Elastic Modulie

Question

When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L +l). The elastic potential energy stored in the extended wire is

Moderate

A

$\frac{1}{2} MgL$
B

Mgl
C

MgL
D

$\frac{1}{2} Mg l$

Solution

Strain = $\frac{l}{L}, stress = \frac{Mg}{A}$
Energy = $\frac{1}{2} \times stress \times strain \times volume$
= $\frac{1}{2} \times \frac{Mg}{A} \times \frac{l}{L} \times A \times L = \frac{1}{2} Mg l$

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