When a body of mass $$1.0$$ kg is suspended from a certain light spring hanging vertically, its length increases by $$5$$ cm. By suspending $$2.0$$ kg block to the spring and if the block is pulled through $$10$$ cm and released the maximum velocity in it in $$m/s$$ is : (Acceleration$$ due to gravity $$=10m$$$$/$$$$s2)

Question

When a body of mass $$1.0$$ kg is suspended from a certain light spring hanging vertically, its length increases by $$5$$ cm. By suspending $$2.0$$ kg block to the spring and if the block is pulled through $$10$$ cm and released the maximum velocity in it in $$m/s$$ is : (Acceleration$$ due to gravity  $$=10m$$​$$/$$​$$s2)

Infinity Learn · Accepted Answer

Initially when $$1$$ kg mass is suspended then by using $$F=$$$$kx$$⇒$$mg=$$$$kx$$⇒$$k=mgx=1$$×$$105$$×$$10$$−$$2=200Nm$$      Further, the angular frequency of oscillation of $$2$$ kg mass is  ω$$=kM=2002=10$$ $$rad/$$$$sec$$ Hence,  $$vmax=a$$ω$$=(10$$×$$10$$−$$2)$$×$$10=1$$ $$m/s$$

When a body of mass 1.0 kg is suspended from a certain light spring hanging vertically, its length increases by 5 cm. By suspending 2.0 kg block to the spring and if the block is pulled through 10 cm and released the maximum velocity in it in m/s is : (Acceleration due to gravity $= 10 m / s^{2})$

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When a body of mass 1.0 kg is suspended from a certain light spring hanging vertically, its length increases by 5 cm. By suspending 2.0 kg block to the spring and if the block is pulled through 10 cm and released the maximum velocity in it in m/s is : (Acceleration due to gravity =10m​/​s2)

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Ready to Test Your Skills?

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When a body of mass 1.0 kg is suspended from a certain light spring hanging vertically, its length increases by 5 cm. By suspending 2.0 kg block to the spring and if the block is pulled through 10 cm and released the maximum velocity in it in m/s is : (Acceleration due to gravity $= 10 m / s^{2})$