When a cell is short circuited, rate of heat generation in it is 25 W. When the terminals of the cell are connected to the ends of a variable resistance R, maximum possible power dissipated in R is
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answer is 3.
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Detailed Solution
If r be the internal resistance of the cell, then ε2r=25In the second case, maximum power will be generated in R when R=r.∴Pmax=(εR+r)2R=(εr+r)2r=ε24r=254W=6.25 W