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When a centimeter thick surface is illuminated with light of wavelength λ, the stopping potential is V. When the same surface is illuminated by light of wavelength 2λ,thestopping potential is V/3. Threshold wavelength for the metallic surface is

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a

4λ/3

b

4λ

c

6λ

d

8λ/3

answer is B.

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Detailed Solution

Case 1 : eV=hc1λ−1λ0Case 2 : eV3=hc12λ−1λ0 Dividing Eq. (i) and (ii), we get ⇒λ0=4λ .

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