When a certain metallic surface is illuminated with monochromatic light of wavelength λ the stopping potential for photoelectric current is 3V0 and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0.The threshold wavelength of this surface for photoelectric effect is
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a
6λ
b
4λ/3
c
4λ
d
8λ
answer is C.
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Detailed Solution
Using photoelectric equation,hv−hv0=12mv2=eVs or hcλ−hcλ0=eVs For the first case, hcλ−hcλ0=e3V0......(i) For the second case, hc2λ−hcλ0=eV0 ......(ii) Solving λ0=4λ
When a certain metallic surface is illuminated with monochromatic light of wavelength λ the stopping potential for photoelectric current is 3V0 and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0.The threshold wavelength of this surface for photoelectric effect is