When a certain weight is suspended from a long uniform wire, its length increases by one cm. If the same weight is suspended from another wire of the same material and length but having a diameter half of the first one then the increase in length will be
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a
0.5 cm
b
2 cm
c
4 cm
d
8 cm
answer is C.
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Detailed Solution
l=FLAY⇒l∝1r2 (F,L and Y are constant )l2l1=r1r22=(2)2=4⇒l2=4l1=4cm