First slide

Thermal expansion

Question

When copper rod of length $‘ l ’$ is heated by $∆ t,$ percentage increase in length is 1% . If copper plate of area $(2 l \times l)$ is heated by $(2 ∆ t),$ percentage increase in area is

Easy

A

1 %
B

2 %
C

4 %
D

8 %

Solution

$\begin{array}{l} \frac{Δ A}{A} \times 100 = 2 (\frac{Δ l}{l} \times 100) = 2 α \times 2 Δ t (∵ Δ t' = 2 Δ t) \end{array}$

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