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when the current change from + 2A  to   2A 2 A in 0.05 s, an e.m.f. of 8 V is induced in a coil. The coefficient of self-induction of the coil is

a
0.1 H
b
0.2 H
c
0.4 H
d
0.8 H

detailed solution

Correct option is A

|e|=Ldidt⇒8=L×(2−(−2))0.05⇒L=0.1H

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