First slide

Inductance

Question

when the current change from $+ 2 A to - 2 A$ 2 A in 0.05 s, an e.m.f. of 8 V is induced in a coil. The coefficient of self-induction of the coil is

Easy

A

0.1 H
B

0.2 H
C

0.4 H
D

0.8 H

Solution

$| e | = L \frac{di}{dt} \Rightarrow 8 = L \times \frac{(2 - (- 2))}{0 .05} \Rightarrow L = 0 .1 H$

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