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When the current changes from + 2 A to - 2A in 0.05 s, an emf of 8 V is induced in a coil. The coefficient of self-induction of the coil is :

a
0.2 H
b
0.4 H
c
0.8 H
d
0.1 H

detailed solution

Correct option is D

e=-L∆i∆t⇒L=e-∆i/∆t

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