Questions
When the current changes from + 2 A to - 2 A in 0.05 second, an e.m.f. of 8 V is induced in a coil. The coefficient of self-induction of the coil is
detailed solution
Correct option is A
We know that, e = -L(di / dt)∴ L=−e(di/dt)=−8(−4/0⋅05)=0⋅1 henryTalk to our academic expert!
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