First slide

Inductance

Question

When the current changes from + 2 A to - 2 A in 0.05 second, an e.m.f. of 8 V is induced in a coil. The coefficient of self-induction of the coil is

Easy

A

0.1 H
B

0.2 H
C

0.4 H
D

0.8 H

Solution

We know that, e = -L(di / dt)
$∴ L = - \frac{e}{(di / dt)} = - \frac{8}{(- 4 / 0 \cdot 05)} = 0 \cdot 1 henry$

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