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Q.

When the current in a coil changes from 8 amperes to 2 amperes in 3 x 10-2 second, the e.m.f. induced in the coil is 2 volt. The self-inductance of the coil, in milli-henry is

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a

1

b

5

c

50

d

10

answer is D.

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Detailed Solution

e=Ldidt 2=L(8−2)3×10−2=L2×102∴L=22×102=10−2H=10mH

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