First slide

Inductance

Question

When the current in a coil changes from 8 amperes to 2 amperes in 3 x 10^-2 second, the e.m.f. induced in the coil is 2 volt. The self-inductance of the coil, in milli-henry is

Easy

A

1
B

5
C

50
D

10

Solution

$e = L \frac{di}{dt} \begin{array}{l} 2 = L [\frac{(8 - 2)}{3 \times 10^{- 2}}] = L (2 \times 10^{2}) \\ ∴ L = \frac{2}{2 \times 10^{2}} = 10^{- 2} H = 10 mH \end{array}$

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